x^2+0.0022x-0.000012=0

Solution for x^2+0.0022x-0.000012=0 equation:

x^2+0.0022x-0.000012=0

We add all the numbers together, and all the variables

x^2+0.0022x-5-1.2E=0

We add all the numbers together, and all the variables

x^2+0.0022x-8.2619381941509=0

a = 1; b = 0.0022; c = -8.2619381941509;
Δ = b2-4ac
Δ = 0.00222-4·1·(-8.2619381941509)
Δ = 33.047757616604
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.0022)-\sqrt{33.047757616604}}{2*1}=\frac{-0.0022-\sqrt{33.047757616604}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.0022)+\sqrt{33.047757616604}}{2*1}=\frac{-0.0022+\sqrt{33.047757616604}}{2}
$